88的雷达2+2+1=5
yang_zhiyu
2023-11-11 10:40:26
#include <bits/stdc++.h>
using namespace std;
typedef int ll;
inline ll read()
{
ll s=0;
bool f=0;
char ch=' ';
while(!isdigit(ch))
{
f|=(ch=='-'); ch=getchar();
}
while(isdigit(ch))
{
s=(s<<3)+(s<<1)+(ch^48); ch=getchar();
}
return (f)?(-s):(s);
}
#define R(x) x=read()
inline void write(ll x)
{
if(x<0)
{
putchar('-'); x=-x;
}
if(x<10)
{
putchar(x+'0'); return;
}
write(x/10);
putchar((x%10)+'0');
return;
}
#define W(x) write(x),putchar(' ')
#define Wl(x) write(x),putchar('\n')
const int Mod=10007;
const int N=1005;
ll Jiec[N];
inline ll Ksm(ll x,ll y)
{
x%=Mod;
ll ans=1;
while(y)
{
if(y&1) ans=ans*x%Mod;
x=x*x%Mod;
y>>=1;
}
return ans;
}
inline ll C(ll n,ll m)
{
return Jiec[n]*Ksm(Jiec[m],Mod-2)%Mod*Ksm(Jiec[n-m],Mod-2)%Mod;
}
int main()
{
int i,j;
int a,b,k,n,m;
R(a); R(b); R(k); R(n); R(m);
Jiec[0]=1;
for(i=1;i<=k;i++) Jiec[i]=Jiec[i-1]*i%Mod;
Wl(Ksm(a,n)*Ksm(b,m)%Mod*C(n+m,n)%Mod);
return 0;
}